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27-1/2x^2=0
Domain of the equation: 2x^2!=0We multiply all the terms by the denominator
x^2!=0/2
x^2!=√0
x!=0
x∈R
27*2x^2-1=0
Wy multiply elements
54x^2-1=0
a = 54; b = 0; c = -1;
Δ = b2-4ac
Δ = 02-4·54·(-1)
Δ = 216
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{216}=\sqrt{36*6}=\sqrt{36}*\sqrt{6}=6\sqrt{6}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-6\sqrt{6}}{2*54}=\frac{0-6\sqrt{6}}{108} =-\frac{6\sqrt{6}}{108} =-\frac{\sqrt{6}}{18} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+6\sqrt{6}}{2*54}=\frac{0+6\sqrt{6}}{108} =\frac{6\sqrt{6}}{108} =\frac{\sqrt{6}}{18} $
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